What are the solutions to the equation x^2+x=110 ?

The solutions to the equation x^2+x=110 are x=10,x=-11

Find the zeros of x^2+x=110

The zeros of x^2+x=110 are x=10,x=-11

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x^{2} + x = 110

x = 10, x = - 11

Solution steps

x^{2} + x = 110

Move

110

to the left side

x^{2} + x - 110 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 110 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 110) = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 \cdot 1}, x_{2} = \frac{- 1 - 21}{2 \cdot 1}

x = \frac{- 1 + 21}{2 \cdot 1} : 10

x = \frac{- 1 - 21}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 10, x = - 11

(5 x - 15)^{2} = - 100

π x^{2} + π x - 9 = 0

\frac{1}{20} x^{2} + 2 x + 100 = 0

4^{2} = 3^{2} + c^{2}

x^{2} = 7 x - 3

What are the solutions to the equation x^2+x=110 ?
The solutions to the equation x^2+x=110 are x=10,x=-11
Find the zeros of x^2+x=110
The zeros of x^2+x=110 are x=10,x=-11