What are the solutions to the equation 4^2=3^2+c^2 ?

The solutions to the equation 4^2=3^2+c^2 are c=sqrt(7),c=-sqrt(7)

Find the zeros of 4^2=3^2+c^2

The zeros of 4^2=3^2+c^2 are c=sqrt(7),c=-sqrt(7)

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4^{2} = 3^{2} + c^{2}

c = 7, c = - 7

Decimal Notation

c = 2.64575 \dots, c = - 2.64575 \dots

Solution steps

4^{2} = 3^{2} + c^{2}

Switch sides

3^{2} + c^{2} = 4^{2}

Move

3^{2}

to the right side

c^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 7, c = - 7

x^{2} = 7 x - 3

8 b^{2} - 3 b - 22 = 0

x (x - 19) = - 90

2 x^{2} - 16 = 34

2 x^{2} + 6 x - 216 = 0

What are the solutions to the equation 4^2=3^2+c^2 ?
The solutions to the equation 4^2=3^2+c^2 are c=sqrt(7),c=-sqrt(7)
Find the zeros of 4^2=3^2+c^2
The zeros of 4^2=3^2+c^2 are c=sqrt(7),c=-sqrt(7)