What are the solutions to the equation 2x^2+6x-216=0 ?

The solutions to the equation 2x^2+6x-216=0 are x=9,x=-12

Find the zeros of 2x^2+6x-216=0

The zeros of 2x^2+6x-216=0 are x=9,x=-12

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2 x^{2} + 6 x - 216 = 0

x = 9, x = - 12

Solution steps

2 x^{2} + 6 x - 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 216 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 216) = 42

x_{1, 2} = \frac{- 6 \pm 42}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 42}{2 \cdot 2}, x_{2} = \frac{- 6 - 42}{2 \cdot 2}

x = \frac{- 6 + 42}{2 \cdot 2} : 9

x = \frac{- 6 - 42}{2 \cdot 2} : - 12

The solutions to the quadratic equation are:

x = 9, x = - 12

- 37 x + 12 x^{2} - 79 = 0

3 x^{2} + 4 x = 3

3 x^{2} + 4 x = 7

3 x^{2} = 9 x - 5

- 5 x^{2} - 2 x + 9 = - 4 x^{2}

What are the solutions to the equation 2x^2+6x-216=0 ?
The solutions to the equation 2x^2+6x-216=0 are x=9,x=-12
Find the zeros of 2x^2+6x-216=0
The zeros of 2x^2+6x-216=0 are x=9,x=-12