What are the solutions to the equation 3x^2+4x=7 ?

The solutions to the equation 3x^2+4x=7 are x=1,x=-7/3

Find the zeros of 3x^2+4x=7

The zeros of 3x^2+4x=7 are x=1,x=-7/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 4 x = 7

x = 1, x = - \frac{7}{3}

Decimal Notation

x = 1, x = - 2.33333 \dots

Solution steps

3 x^{2} + 4 x = 7

Move

7

to the left side

3 x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 7) = 10

x_{1, 2} = \frac{- 4 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 10}{2 \cdot 3}, x_{2} = \frac{- 4 - 10}{2 \cdot 3}

x = \frac{- 4 + 10}{2 \cdot 3} : 1

x = \frac{- 4 - 10}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{7}{3}

3 x^{2} = 9 x - 5

- 5 x^{2} - 2 x + 9 = - 4 x^{2}

(z + 2)^{2} = 2

t, (- t (- t + 13) + k) = 0

\frac{( x ^{2} )}{( 0.295 )} = 2.29 \times 1 0^{- 6}

What are the solutions to the equation 3x^2+4x=7 ?
The solutions to the equation 3x^2+4x=7 are x=1,x=-7/3
Find the zeros of 3x^2+4x=7
The zeros of 3x^2+4x=7 are x=1,x=-7/3