What are the solutions to the equation (z+2)^2=2 ?

The solutions to the equation (z+2)^2=2 are z=sqrt(2)-2,z=-sqrt(2)-2

Find the zeros of (z+2)^2=2

The zeros of (z+2)^2=2 are z=sqrt(2)-2,z=-sqrt(2)-2

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(z + 2)^{2} = 2

z = 2 - 2, z = - 2 - 2

Decimal Notation

z = - 0.58578 \dots, z = - 3.41421 \dots

Solution steps

(z + 2)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 2 = 2 : z = 2 - 2

Solve

z + 2 = - 2 : z = - 2 - 2

The solutions to the quadratic equation are:

z = 2 - 2, z = - 2 - 2

t, (- t (- t + 13) + k) = 0

\frac{( x ^{2} )}{( 0.295 )} = 2.29 \times 1 0^{- 6}

x^{2} + 8 x + 240 = 0

x^{2} - 10 x = 39

x^{2} - 10 x = 40

What are the solutions to the equation (z+2)^2=2 ?
The solutions to the equation (z+2)^2=2 are z=sqrt(2)-2,z=-sqrt(2)-2
Find the zeros of (z+2)^2=2
The zeros of (z+2)^2=2 are z=sqrt(2)-2,z=-sqrt(2)-2