What are the solutions to the equation -2x^2+24x-72=0 ?

The solutions to the equation -2x^2+24x-72=0 are x=6

Find the zeros of -2x^2+24x-72=0

The zeros of -2x^2+24x-72=0 are x=6

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- 2 x^{2} + 24 x - 72 = 0

x = 6

Solution steps

- 2 x^{2} + 24 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 2 ) ( - 72 )}{2 ( - 2 )}

2 4^{2} - 4 (- 2) (- 72) = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 ( - 2 )}

x = \frac{- 24}{2 ( - 2 )}

\frac{- 24}{2 ( - 2 )} = 6

x = 6

The solution to the quadratic equation is:

x = 6

x^{2} - 13 x - 22 = 0

9 x^{2} - 4 x - 7 = 0

x^{2} - 4 x - 30 = 0

16 p^{2} - 9 = 0

x^{2} + 12 x + 100 = 0

What are the solutions to the equation -2x^2+24x-72=0 ?
The solutions to the equation -2x^2+24x-72=0 are x=6
Find the zeros of -2x^2+24x-72=0
The zeros of -2x^2+24x-72=0 are x=6