What are the solutions to the equation x^2-4=1 ?

The solutions to the equation x^2-4=1 are x=sqrt(5),x=-sqrt(5)

Find the zeros of x^2-4=1

The zeros of x^2-4=1 are x=sqrt(5),x=-sqrt(5)

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x^{2} - 4 = 1

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

x^{2} - 4 = 1

Move

4

to the right side

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

x^{2} - 4 = 2

2 x^{2} + 4 x - 3 = 0

x^{2} + 6 x + 8 = 35

- 11 p = - 22 - p^{2}

h^{2} = 100

What are the solutions to the equation x^2-4=1 ?
The solutions to the equation x^2-4=1 are x=sqrt(5),x=-sqrt(5)
Find the zeros of x^2-4=1
The zeros of x^2-4=1 are x=sqrt(5),x=-sqrt(5)