What are the solutions to the equation x^2-4=2 ?

The solutions to the equation x^2-4=2 are x=sqrt(6),x=-sqrt(6)

Find the zeros of x^2-4=2

The zeros of x^2-4=2 are x=sqrt(6),x=-sqrt(6)

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x^{2} - 4 = 2

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

x^{2} - 4 = 2

Move

4

to the right side

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

2 x^{2} + 4 x - 3 = 0

x^{2} + 6 x + 8 = 35

- 11 p = - 22 - p^{2}

h^{2} = 100

x, x^{2} + 8 x + y^{2} + 10 y + 41 = 0

What are the solutions to the equation x^2-4=2 ?
The solutions to the equation x^2-4=2 are x=sqrt(6),x=-sqrt(6)
Find the zeros of x^2-4=2
The zeros of x^2-4=2 are x=sqrt(6),x=-sqrt(6)