What are the solutions to the equation 18x^2+12x+15=8x^2+5 ?

The solutions to the equation 18x^2+12x+15=8x^2+5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5

Find the zeros of 18x^2+12x+15=8x^2+5

The zeros of 18x^2+12x+15=8x^2+5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5

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18 x^{2} + 12 x + 15 = 8 x^{2} + 5

x = - \frac{3}{5} + i \frac{4}{5}, x = - \frac{3}{5} - i \frac{4}{5}

Solution steps

18 x^{2} + 12 x + 15 = 8 x^{2} + 5

Move

5

to the left side

18 x^{2} + 12 x + 10 = 8 x^{2}

Move

8 x^{2}

to the left side

10 x^{2} + 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

1 2^{2} - 4 \cdot 10 \cdot 10 : 16 i

x_{1, 2} = \frac{- 12 \pm 16 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 12 + 16 i}{2 \cdot 10}, x_{2} = \frac{- 12 - 16 i}{2 \cdot 10}

x = \frac{- 12 + 16 i}{2 \cdot 10} : - \frac{3}{5} + i \frac{4}{5}

x = \frac{- 12 - 16 i}{2 \cdot 10} : - \frac{3}{5} - i \frac{4}{5}

The solutions to the quadratic equation are:

x = - \frac{3}{5} + i \frac{4}{5}, x = - \frac{3}{5} - i \frac{4}{5}

y^{2} = \frac{3}{4}

x^{2} + 10 x + 4.75 = 0

\frac{1}{2} (x - 1)^{2} - 4 = - 1

12 - x^{2} = x^{2} - 2 x

a^{2} - 5 a - 14 = 0

What are the solutions to the equation 18x^2+12x+15=8x^2+5 ?
The solutions to the equation 18x^2+12x+15=8x^2+5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5
Find the zeros of 18x^2+12x+15=8x^2+5
The zeros of 18x^2+12x+15=8x^2+5 are x=-3/5+i 4/5 ,x=-3/5-i 4/5