What are the solutions to the equation y^2= 3/4 ?

The solutions to the equation y^2= 3/4 are y=(sqrt(3))/2 ,y=-(sqrt(3))/2

Find the zeros of y^2= 3/4

The zeros of y^2= 3/4 are y=(sqrt(3))/2 ,y=-(sqrt(3))/2

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y^{2} = \frac{3}{4}

y = \frac{3}{2}, y = - \frac{3}{2}

Decimal Notation

y = 0.86602 \dots, y = - 0.86602 \dots

Solution steps

y^{2} = \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{3}{4}, y = - \frac{3}{4}

\frac{3}{4} = \frac{3}{2}

- \frac{3}{4} = - \frac{3}{2}

y = \frac{3}{2}, y = - \frac{3}{2}

x^{2} + 10 x + 4.75 = 0

\frac{1}{2} (x - 1)^{2} - 4 = - 1

12 - x^{2} = x^{2} - 2 x

a^{2} - 5 a - 14 = 0

2 x^{2} = x - 4

What are the solutions to the equation y^2= 3/4 ?
The solutions to the equation y^2= 3/4 are y=(sqrt(3))/2 ,y=-(sqrt(3))/2
Find the zeros of y^2= 3/4
The zeros of y^2= 3/4 are y=(sqrt(3))/2 ,y=-(sqrt(3))/2