What are the solutions to the equation -2x^2+2x+8=0 ?

The solutions to the equation -2x^2+2x+8=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2

Find the zeros of -2x^2+2x+8=0

The zeros of -2x^2+2x+8=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2

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- 2 x^{2} + 2 x + 8 = 0

x = - \frac{- 1 + 17}{2}, x = \frac{1 + 17}{2}

Decimal Notation

x = - 1.56155 \dots, x = 2.56155 \dots

Solution steps

- 2 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 2 ) \cdot 8}{2 ( - 2 )}

2^{2} - 4 (- 2) \cdot 8 = 217

x_{1, 2} = \frac{- 2 \pm 2 17}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 17}{2 ( - 2 )}, x_{2} = \frac{- 2 - 2 17}{2 ( - 2 )}

x = \frac{- 2 + 2 17}{2 ( - 2 )} : - \frac{- 1 + 17}{2}

x = \frac{- 2 - 2 17}{2 ( - 2 )} : \frac{1 + 17}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 17}{2}, x = \frac{1 + 17}{2}

x, x^{2} y + x y^{2} = 4

u^{2} + 10 u + 24 = 0

x^{2} - 9 x - 5 = 23

16 x^{2} + 16 x + 3 = 0

x, (y - 4)^{2} + 20 (x + 3)^{2} = 0

What are the solutions to the equation -2x^2+2x+8=0 ?
The solutions to the equation -2x^2+2x+8=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2
Find the zeros of -2x^2+2x+8=0
The zeros of -2x^2+2x+8=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2