What are the solutions to the equation -6(x+5)^2=120 ?

The solutions to the equation -6(x+5)^2=120 are x=2sqrt(5)i-5,x=-2sqrt(5)i-5

Find the zeros of -6(x+5)^2=120

The zeros of -6(x+5)^2=120 are x=2sqrt(5)i-5,x=-2sqrt(5)i-5

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- 6 (x + 5)^{2} = 120

x = 25 i - 5, x = - 25 i - 5

Solution steps

- 6 (x + 5)^{2} = 120

Divide both sides by

- 6

(x + 5)^{2} = - 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = - 20 : x = 25 i - 5

Solve

x + 5 = - - 20 : x = - 25 i - 5

The solutions to the quadratic equation are:

x = 25 i - 5, x = - 25 i - 5

2 x^{2} - 30 x + 24 = 3 x - x^{2} - 48

3 x^{2} - 14 x + 12 = 0

3 x (x - 2) - x (x + 1) + 5 = 0

x^{2} + 64 x - 32000 = 0

3 - x^{2} = x + 1

What are the solutions to the equation -6(x+5)^2=120 ?
The solutions to the equation -6(x+5)^2=120 are x=2sqrt(5)i-5,x=-2sqrt(5)i-5
Find the zeros of -6(x+5)^2=120
The zeros of -6(x+5)^2=120 are x=2sqrt(5)i-5,x=-2sqrt(5)i-5