What are the solutions to the equation -2x^2+2=2.5 ?

The solutions to the equation -2x^2+2=2.5 are x= 1/2 i,x=-1/2 i

Find the zeros of -2x^2+2=2.5

The zeros of -2x^2+2=2.5 are x= 1/2 i,x=-1/2 i

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- 2 x^{2} + 2 = 2.5

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

- 2 x^{2} + 2 = 2.5

Move

2

to the right side

- 2 x^{2} = 0.5

Divide both sides by

- 2

x^{2} = - 0.25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 0.25, x = - - 0.25

- 0.25 = \frac{1}{2} i

- - 0.25 = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

- (x - 3)^{2} + 4 = 0

(a x^{2} + 3 b x + 8) + (2 x^{2} - 4 x + c) = 5 x^{2} - 2 x + 3

n^{2} - 24 n

x^{2} - 7 x = - 1

y^{2} - 5 y - 84 = 0

What are the solutions to the equation -2x^2+2=2.5 ?
The solutions to the equation -2x^2+2=2.5 are x= 1/2 i,x=-1/2 i
Find the zeros of -2x^2+2=2.5
The zeros of -2x^2+2=2.5 are x= 1/2 i,x=-1/2 i