What are the solutions to the equation 25=10x-x^2 ?

The solutions to the equation 25=10x-x^2 are x=5

Find the zeros of 25=10x-x^2

The zeros of 25=10x-x^2 are x=5

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25 = 10 x - x^{2}

x = 5

Solution steps

25 = 10 x - x^{2}

Switch sides

10 x - x^{2} = 25

Move

25

to the left side

10 x - x^{2} - 25 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 ( - 1 )}

x = \frac{- 10}{2 ( - 1 )}

\frac{- 10}{2 ( - 1 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

- x^{2} + 7 x + 18 = 0

y^{2} + 14 y

7 r^{2} + 84 = - 49 r

y^{2} + 16 y

x^{2} - 11 x - 12 = 0

What are the solutions to the equation 25=10x-x^2 ?
The solutions to the equation 25=10x-x^2 are x=5
Find the zeros of 25=10x-x^2
The zeros of 25=10x-x^2 are x=5