What are the solutions to the equation -8x^2+8x-2=0 ?

The solutions to the equation -8x^2+8x-2=0 are x= 1/2

Find the zeros of -8x^2+8x-2=0

The zeros of -8x^2+8x-2=0 are x= 1/2

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- 8 x^{2} + 8 x - 2 = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

- 8 x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 8 ) ( - 2 )}{2 ( - 8 )}

8^{2} - 4 (- 8) (- 2) = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 ( - 8 )}

x = \frac{- 8}{2 ( - 8 )}

\frac{- 8}{2 ( - 8 )} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

5 (m - 4)^{2} = 40

n^{2} - n - 90 = 0

- 16 a^{2} + 3 a = - 7 a^{2} + 10

y^{2} + 6 y - 16 = 0

\frac{1}{3} x^{2} - 2 x + 3 = 0

What are the solutions to the equation -8x^2+8x-2=0 ?
The solutions to the equation -8x^2+8x-2=0 are x= 1/2
Find the zeros of -8x^2+8x-2=0
The zeros of -8x^2+8x-2=0 are x= 1/2