What are the solutions to the equation 1/3 x^2-2x+3=0 ?

The solutions to the equation 1/3 x^2-2x+3=0 are x=3

Find the zeros of 1/3 x^2-2x+3=0

The zeros of 1/3 x^2-2x+3=0 are x=3

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\frac{1}{3} x^{2} - 2 x + 3 = 0

x = 3

Solution steps

\frac{1}{3} x^{2} - 2 x + 3 = 0

Multiply both sides by

3

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

(3 x - 2) (2 x + 5) = 0

\frac{x}{2} \cdot \frac{x}{5} = 160

A (x) = 2 x^{2} + 20 x

x^{2} + x + \frac{5}{4}

(x - 1)^{2} + 4 = 0

What are the solutions to the equation 1/3 x^2-2x+3=0 ?
The solutions to the equation 1/3 x^2-2x+3=0 are x=3
Find the zeros of 1/3 x^2-2x+3=0
The zeros of 1/3 x^2-2x+3=0 are x=3