What are the solutions to the equation A(x)=2x^2+20x ?

The solutions to the equation A(x)=2x^2+20x are x=0,x=(A-20)/2

Find the zeros of A(x)=2x^2+20x

The zeros of A(x)=2x^2+20x are x=0,x=(A-20)/2

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A (x) = 2 x^{2} + 20 x

x = 0, x = \frac{A - 20}{2}

Solution steps

A (x) = 2 x^{2} + 20 x

Refine

A x = 2 x^{2} + 20 x

Switch sides

2 x^{2} + 20 x = A x

Move

A x

to the left side

2 x^{2} + 20 x - A x = 0

Factor

2 x^{2} + 20 x - A x : x (2 x - A + 20)

x (2 x - A + 20) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - A + 20 = 0

Solve

2 x - A + 20 = 0 : x = \frac{A - 20}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{A - 20}{2}

x^{2} + x + \frac{5}{4}

(x - 1)^{2} + 4 = 0

x, y = 24 - 6 x^{2}

(x + 7)^{2} + 28 = 0

3 x^{2} - 8 x - 9 = 0

What are the solutions to the equation A(x)=2x^2+20x ?
The solutions to the equation A(x)=2x^2+20x are x=0,x=(A-20)/2
Find the zeros of A(x)=2x^2+20x
The zeros of A(x)=2x^2+20x are x=0,x=(A-20)/2