What are the solutions to the equation solvefor x,x^2+3x+h=9+h ?

The solutions to the equation solvefor x,x^2+3x+h=9+h are x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2

Find the zeros of solvefor x,x^2+3x+h=9+h

The zeros of solvefor x,x^2+3x+h=9+h are x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2

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solve for

x, x^{2} + 3 x + h = 9 + h

x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

Decimal Notation

x = 1.85410 \dots, x = - 4.85410 \dots

Solution steps

x^{2} + 3 x + h = 9 + h

Move

h

to the left side

x^{2} + 3 x = 9

Move

9

to the left side

x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 9) = 35

x_{1, 2} = \frac{- 3 \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3 5}{2 \cdot 1}, x_{2} = \frac{- 3 - 3 5}{2 \cdot 1}

x = \frac{- 3 + 3 5}{2 \cdot 1} : \frac{- 3 + 3 5}{2}

x = \frac{- 3 - 3 5}{2 \cdot 1} : \frac{- 3 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

(x + 9) (2 x + 1) = 100

6 x^{2} - 24 x = 30

0 = - 16 t^{2} + 12 t + 120

(x + 1) (2 x + 3) (3 x + 4) = (6 x^{2} + 5) (x - 3)

4 y^{2} + y - 3 = 0

What are the solutions to the equation solvefor x,x^2+3x+h=9+h ?
The solutions to the equation solvefor x,x^2+3x+h=9+h are x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2
Find the zeros of solvefor x,x^2+3x+h=9+h
The zeros of solvefor x,x^2+3x+h=9+h are x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2