What are the solutions to the equation p^2-3p=0 ?

The solutions to the equation p^2-3p=0 are p=3,p=0

Find the zeros of p^2-3p=0

The zeros of p^2-3p=0 are p=3,p=0

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p^{2} - 3 p = 0

p = 3, p = 0

Solution steps

p^{2} - 3 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

p_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, p_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

p = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

p = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 3, p = 0

1.3 x^{2} + 7 x = 0

4 x^{2} - 90 = 10

x, 2 x^{2} + y^{2} + 3 \cdot x \cdot y = 1

x^{2} - 10 x - 1 = 0

(2 x + 3)^{2} - 4 = 0

What are the solutions to the equation p^2-3p=0 ?
The solutions to the equation p^2-3p=0 are p=3,p=0
Find the zeros of p^2-3p=0
The zeros of p^2-3p=0 are p=3,p=0