What are the solutions to the equation solvefor x,x^2+y^3=2 ?

The solutions to the equation solvefor x,x^2+y^3=2 are x=sqrt(2-y^3),x=-sqrt(2-y^3)

Find the zeros of solvefor x,x^2+y^3=2

The zeros of solvefor x,x^2+y^3=2 are x=sqrt(2-y^3),x=-sqrt(2-y^3)

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solve for

x, x^{2} + y^{3} = 2

x = 2 - y^{3}, x = - 2 - y^{3}

Solution steps

x^{2} + y^{3} = 2

Move

y^{3}

to the right side

x^{2} = 2 - y^{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2 - y^{3}, x = - 2 - y^{3}

2 x^{2} + 2 x + 1

8^{2} + 3^{2} = c^{2}

- k^{2} - 65 k + 720 = 0

- 16 x^{2} + 85 x = 0

x^{2} - 7 x = 0

What are the solutions to the equation solvefor x,x^2+y^3=2 ?
The solutions to the equation solvefor x,x^2+y^3=2 are x=sqrt(2-y^3),x=-sqrt(2-y^3)
Find the zeros of solvefor x,x^2+y^3=2
The zeros of solvefor x,x^2+y^3=2 are x=sqrt(2-y^3),x=-sqrt(2-y^3)