What are the solutions to the equation solvefor x,x^2-4x=y^2-4y ?

The solutions to the equation solvefor x,x^2-4x=y^2-4y are x=y,x=-y+4

Find the zeros of solvefor x,x^2-4x=y^2-4y

The zeros of solvefor x,x^2-4x=y^2-4y are x=y,x=-y+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} - 4 x = y^{2} - 4 y

x = y, x = - y + 4

Solution steps

x^{2} - 4 x = y^{2} - 4 y

Move

4 y

to the left side

x^{2} - 4 x + 4 y = y^{2}

Move

y^{2}

to the left side

x^{2} - 4 x + 4 y - y^{2} = 0

Factor

x^{2} - 4 x + 4 y - y^{2} : (x - y) (x + y - 4)

(x - y) (x + y - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - y = 0 or x + y - 4 = 0

Solve

x - y = 0 : x = y

Solve

x + y - 4 = 0 : x = - y + 4

The solutions to the quadratic equation are:

x = y, x = - y + 4

x^{2} + 5 x - 36 = 0

2 x - 5 = - x^{2}

4 (x^{2} - 6 x) = 24

0 = \frac{1}{2} (x - 4)^{2} - 2

x^{2} + 14 x + 12 = 0

What are the solutions to the equation solvefor x,x^2-4x=y^2-4y ?
The solutions to the equation solvefor x,x^2-4x=y^2-4y are x=y,x=-y+4
Find the zeros of solvefor x,x^2-4x=y^2-4y
The zeros of solvefor x,x^2-4x=y^2-4y are x=y,x=-y+4