What are the solutions to the equation 0= 1/2 (x-4)^2-2 ?

The solutions to the equation 0= 1/2 (x-4)^2-2 are x=6,x=2

Find the zeros of 0= 1/2 (x-4)^2-2

The zeros of 0= 1/2 (x-4)^2-2 are x=6,x=2

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0 = \frac{1}{2} (x - 4)^{2} - 2

x = 6, x = 2

Solution steps

0 = \frac{1}{2} (x - 4)^{2} - 2

Switch sides

\frac{1}{2} (x - 4)^{2} - 2 = 0

Move

2

to the right side

\frac{1}{2} (x - 4)^{2} = 2

Multiply both sides by

2

(x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

x^{2} + 14 x + 12 = 0

9 x^{2} + 9 x = 28

2 y^{2} - 20 y = 0

- x^{2} + 20 x - 126 = 5

15 x^{2} = 135

What are the solutions to the equation 0= 1/2 (x-4)^2-2 ?
The solutions to the equation 0= 1/2 (x-4)^2-2 are x=6,x=2
Find the zeros of 0= 1/2 (x-4)^2-2
The zeros of 0= 1/2 (x-4)^2-2 are x=6,x=2