What are the solutions to the equation 9x^2+9x=28 ?

The solutions to the equation 9x^2+9x=28 are x= 4/3 ,x=-7/3

Find the zeros of 9x^2+9x=28

The zeros of 9x^2+9x=28 are x= 4/3 ,x=-7/3

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9 x^{2} + 9 x = 28

x = \frac{4}{3}, x = - \frac{7}{3}

Decimal Notation

x = 1.33333 \dots, x = - 2.33333 \dots

Solution steps

9 x^{2} + 9 x = 28

Move

28

to the left side

9 x^{2} + 9 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 9 ( - 28 )}{2 \cdot 9}

9^{2} - 4 \cdot 9 (- 28) = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 \cdot 9}, x_{2} = \frac{- 9 - 33}{2 \cdot 9}

x = \frac{- 9 + 33}{2 \cdot 9} : \frac{4}{3}

x = \frac{- 9 - 33}{2 \cdot 9} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{7}{3}

2 y^{2} - 20 y = 0

- x^{2} + 20 x - 126 = 5

15 x^{2} = 135

- 2 = x^{2}

(x - 21)^{2} = 25

What are the solutions to the equation 9x^2+9x=28 ?
The solutions to the equation 9x^2+9x=28 are x= 4/3 ,x=-7/3
Find the zeros of 9x^2+9x=28
The zeros of 9x^2+9x=28 are x= 4/3 ,x=-7/3