What are the solutions to the equation -2=x^2 ?

The solutions to the equation -2=x^2 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of -2=x^2

The zeros of -2=x^2 are x=sqrt(2)i,x=-sqrt(2)i

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- 2 = x^{2}

x = 2 i, x = - 2 i

Solution steps

- 2 = x^{2}

Switch sides

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

(x - 21)^{2} = 25

20 n^{2} - 9 n - 20 = 0

y^{2} - 121 = 0

x, 5 x^{2} - 4 x y + 5 y^{2} - 21 = 0

x, 3 x^{2} - 16 x + 16 = 0

What are the solutions to the equation -2=x^2 ?
The solutions to the equation -2=x^2 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of -2=x^2
The zeros of -2=x^2 are x=sqrt(2)i,x=-sqrt(2)i