What are the solutions to the equation 20n^2-9n-20=0 ?

The solutions to the equation 20n^2-9n-20=0 are n= 5/4 ,n=-4/5

Find the zeros of 20n^2-9n-20=0

The zeros of 20n^2-9n-20=0 are n= 5/4 ,n=-4/5

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20 n^{2} - 9 n - 20 = 0

n = \frac{5}{4}, n = - \frac{4}{5}

Decimal Notation

n = 1.25, n = - 0.8

Solution steps

20 n^{2} - 9 n - 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 20 ( - 20 )}{2 \cdot 20}

(- 9)^{2} - 4 \cdot 20 (- 20) = 41

n_{1, 2} = \frac{- ( - 9 ) \pm 41}{2 \cdot 20}

Separate the solutions

n_{1} = \frac{- ( - 9 ) + 41}{2 \cdot 20}, n_{2} = \frac{- ( - 9 ) - 41}{2 \cdot 20}

n = \frac{- ( - 9 ) + 41}{2 \cdot 20} : \frac{5}{4}

n = \frac{- ( - 9 ) - 41}{2 \cdot 20} : - \frac{4}{5}

The solutions to the quadratic equation are:

n = \frac{5}{4}, n = - \frac{4}{5}

y^{2} - 121 = 0

x, 5 x^{2} - 4 x y + 5 y^{2} - 21 = 0

x, 3 x^{2} - 16 x + 16 = 0

46 = - 16 (t)^{2} + 50 (t) + 10

9 d^{2} + 6 d + 1 = 0

What are the solutions to the equation 20n^2-9n-20=0 ?
The solutions to the equation 20n^2-9n-20=0 are n= 5/4 ,n=-4/5
Find the zeros of 20n^2-9n-20=0
The zeros of 20n^2-9n-20=0 are n= 5/4 ,n=-4/5