What are the solutions to the equation 46=-16(t)^2+50(t)+10 ?

The solutions to the equation 46=-16(t)^2+50(t)+10 are t= 9/8 ,t=2

Find the zeros of 46=-16(t)^2+50(t)+10

The zeros of 46=-16(t)^2+50(t)+10 are t= 9/8 ,t=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

46 = - 16 (t)^{2} + 50 (t) + 10

t = \frac{9}{8}, t = 2

Decimal Notation

t = 1.125, t = 2

Solution steps

46 = - 16 t^{2} + 50 (t) + 10

Refine

46 = - 16 t^{2} + 50 t + 10

Switch sides

- 16 t^{2} + 50 t + 10 = 46

Move

46

to the left side

- 16 t^{2} + 50 t - 36 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 16 ) ( - 36 )}{2 ( - 16 )}

5 0^{2} - 4 (- 16) (- 36) = 14

t_{1, 2} = \frac{- 50 \pm 14}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 50 + 14}{2 ( - 16 )}, t_{2} = \frac{- 50 - 14}{2 ( - 16 )}

t = \frac{- 50 + 14}{2 ( - 16 )} : \frac{9}{8}

t = \frac{- 50 - 14}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

t = \frac{9}{8}, t = 2

9 d^{2} + 6 d + 1 = 0

3 x^{2} - 9 x + 12 = 0

x, x^{2} + 6 x + 9 = 0

r^{2} - r + 2 = 0

3 x^{2} - 42 x + 135 = 0

What are the solutions to the equation 46=-16(t)^2+50(t)+10 ?
The solutions to the equation 46=-16(t)^2+50(t)+10 are t= 9/8 ,t=2
Find the zeros of 46=-16(t)^2+50(t)+10
The zeros of 46=-16(t)^2+50(t)+10 are t= 9/8 ,t=2