What are the solutions to the equation 3x^2-42x+135=0 ?

The solutions to the equation 3x^2-42x+135=0 are x=9,x=5

Find the zeros of 3x^2-42x+135=0

The zeros of 3x^2-42x+135=0 are x=9,x=5

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3 x^{2} - 42 x + 135 = 0

x = 9, x = 5

Solution steps

3 x^{2} - 42 x + 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 3 \cdot 135}{2 \cdot 3}

(- 42)^{2} - 4 \cdot 3 \cdot 135 = 12

x_{1, 2} = \frac{- ( - 42 ) \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 12}{2 \cdot 3}, x_{2} = \frac{- ( - 42 ) - 12}{2 \cdot 3}

x = \frac{- ( - 42 ) + 12}{2 \cdot 3} : 9

x = \frac{- ( - 42 ) - 12}{2 \cdot 3} : 5

The solutions to the quadratic equation are:

x = 9, x = 5

15 x^{2} + 2 x - 8 = 0

x^{2} + x - 100 = 0

x^{2} - 6 x + 40 = 0

x, 4 x^{2} - 24 x + 64 y^{2} + 2 y + 55 = 0

x, x^{2} + 6 x + 4 = 0

What are the solutions to the equation 3x^2-42x+135=0 ?
The solutions to the equation 3x^2-42x+135=0 are x=9,x=5
Find the zeros of 3x^2-42x+135=0
The zeros of 3x^2-42x+135=0 are x=9,x=5