What are the solutions to the equation x^2-6x+40=0 ?

The solutions to the equation x^2-6x+40=0 are x=3+sqrt(31)i,x=3-sqrt(31)i

Find the zeros of x^2-6x+40=0

The zeros of x^2-6x+40=0 are x=3+sqrt(31)i,x=3-sqrt(31)i

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x^{2} - 6 x + 40 = 0

x = 3 + 31 i, x = 3 - 31 i

Solution steps

x^{2} - 6 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 40 : 231 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 1} : 3 + 31 i

x = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 1} : 3 - 31 i

The solutions to the quadratic equation are:

x = 3 + 31 i, x = 3 - 31 i

x, 4 x^{2} - 24 x + 64 y^{2} + 2 y + 55 = 0

x, x^{2} + 6 x + 4 = 0

- 4 x^{2} + 20 x - 9 = 0

k^{2} - 36 = 0

x^{2} = 18 - x^{2}

What are the solutions to the equation x^2-6x+40=0 ?
The solutions to the equation x^2-6x+40=0 are x=3+sqrt(31)i,x=3-sqrt(31)i
Find the zeros of x^2-6x+40=0
The zeros of x^2-6x+40=0 are x=3+sqrt(31)i,x=3-sqrt(31)i