What are the solutions to the equation -4x^2+20x-9=0 ?

The solutions to the equation -4x^2+20x-9=0 are x= 1/2 ,x= 9/2

Find the zeros of -4x^2+20x-9=0

The zeros of -4x^2+20x-9=0 are x= 1/2 ,x= 9/2

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- 4 x^{2} + 20 x - 9 = 0

x = \frac{1}{2}, x = \frac{9}{2}

Decimal Notation

x = 0.5, x = 4.5

Solution steps

- 4 x^{2} + 20 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

2 0^{2} - 4 (- 4) (- 9) = 16

x_{1, 2} = \frac{- 20 \pm 16}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 20 + 16}{2 ( - 4 )}, x_{2} = \frac{- 20 - 16}{2 ( - 4 )}

x = \frac{- 20 + 16}{2 ( - 4 )} : \frac{1}{2}

x = \frac{- 20 - 16}{2 ( - 4 )} : \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{9}{2}

k^{2} - 36 = 0

x^{2} = 18 - x^{2}

11 x^{2} - 11 = 0

n^{2} + 4 = 36

x^{2} + 1.2 x + 1.47 = 0

What are the solutions to the equation -4x^2+20x-9=0 ?
The solutions to the equation -4x^2+20x-9=0 are x= 1/2 ,x= 9/2
Find the zeros of -4x^2+20x-9=0
The zeros of -4x^2+20x-9=0 are x= 1/2 ,x= 9/2