What are the solutions to the equation x^2+1.2x+1.47=0 ?

The solutions to the equation x^2+1.2x+1.47=0 are x=-3/5+i(sqrt(111))/(10),x=-3/5-i(sqrt(111))/(10)

Find the zeros of x^2+1.2x+1.47=0

The zeros of x^2+1.2x+1.47=0 are x=-3/5+i(sqrt(111))/(10),x=-3/5-i(sqrt(111))/(10)

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x^{2} + 1.2 x + 1.47 = 0

x = - \frac{3}{5} + i \frac{111}{10}, x = - \frac{3}{5} - i \frac{111}{10}

Solution steps

x^{2} + 1.2 x + 1.47 = 0

Multiply both sides by

100

100 x^{2} + 120 x + 147 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 120 \pm 12 0 ^{2} - 4 \cdot 100 \cdot 147}{2 \cdot 100}

Simplify

12 0^{2} - 4 \cdot 100 \cdot 147 : 20111 i

x_{1, 2} = \frac{- 120 \pm 20 111 i}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 120 + 20 111 i}{2 \cdot 100}, x_{2} = \frac{- 120 - 20 111 i}{2 \cdot 100}

x = \frac{- 120 + 20 111 i}{2 \cdot 100} : - \frac{3}{5} + i \frac{111}{10}

x = \frac{- 120 - 20 111 i}{2 \cdot 100} : - \frac{3}{5} - i \frac{111}{10}

The solutions to the quadratic equation are:

x = - \frac{3}{5} + i \frac{111}{10}, x = - \frac{3}{5} - i \frac{111}{10}

- 3 x^{2} + 8 x - 4 = 0

x^{2} - 3.25 = 21.75

- 3 x^{2} + 8 x - 3 = 0

25 = - 4.9 t^{2} + 20 t + 20

lo g_{10} (5) (4 x^{2} + 4) - lo g_{10} (5) (x + 6) = 1

What are the solutions to the equation x^2+1.2x+1.47=0 ?
The solutions to the equation x^2+1.2x+1.47=0 are x=-3/5+i(sqrt(111))/(10),x=-3/5-i(sqrt(111))/(10)
Find the zeros of x^2+1.2x+1.47=0
The zeros of x^2+1.2x+1.47=0 are x=-3/5+i(sqrt(111))/(10),x=-3/5-i(sqrt(111))/(10)