What are the solutions to the equation 2x(5x-1)=9 ?

The solutions to the equation 2x(5x-1)=9 are x=(1+sqrt(91))/(10),x=(1-sqrt(91))/(10)

Find the zeros of 2x(5x-1)=9

The zeros of 2x(5x-1)=9 are x=(1+sqrt(91))/(10),x=(1-sqrt(91))/(10)

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2 x (5 x - 1) = 9

x = \frac{1 + 91}{10}, x = \frac{1 - 91}{10}

Decimal Notation

x = 1.05393 \dots, x = - 0.85393 \dots

Solution steps

2 x (5 x - 1) = 9

Expand

2 x (5 x - 1) : 10 x^{2} - 2 x

10 x^{2} - 2 x = 9

Move

9

to the left side

10 x^{2} - 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 ( - 9 )}{2 \cdot 10}

(- 2)^{2} - 4 \cdot 10 (- 9) = 291

x_{1, 2} = \frac{- ( - 2 ) \pm 2 91}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 91}{2 \cdot 10}, x_{2} = \frac{- ( - 2 ) - 2 91}{2 \cdot 10}

x = \frac{- ( - 2 ) + 2 91}{2 \cdot 10} : \frac{1 + 91}{10}

x = \frac{- ( - 2 ) - 2 91}{2 \cdot 10} : \frac{1 - 91}{10}

The solutions to the quadratic equation are:

x = \frac{1 + 91}{10}, x = \frac{1 - 91}{10}

10 x^{2} - 16 x - 8 = 0

0.6 x^{2} + 6 x + 2 = 0

x^{2} - x - 20

9 u^{2} - 30 u = - 25

2 x^{2} + 18 x = 7 x + 21

What are the solutions to the equation 2x(5x-1)=9 ?
The solutions to the equation 2x(5x-1)=9 are x=(1+sqrt(91))/(10),x=(1-sqrt(91))/(10)
Find the zeros of 2x(5x-1)=9
The zeros of 2x(5x-1)=9 are x=(1+sqrt(91))/(10),x=(1-sqrt(91))/(10)