What are the solutions to the equation 2x^2+18x=7x+21 ?

The solutions to the equation 2x^2+18x=7x+21 are x= 3/2 ,x=-7

Find the zeros of 2x^2+18x=7x+21

The zeros of 2x^2+18x=7x+21 are x= 3/2 ,x=-7

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2 x^{2} + 18 x = 7 x + 21

x = \frac{3}{2}, x = - 7

Decimal Notation

x = 1.5, x = - 7

Solution steps

2 x^{2} + 18 x = 7 x + 21

Move

21

to the left side

2 x^{2} + 18 x - 21 = 7 x

Move

7 x

to the left side

2 x^{2} + 11 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 21) = 17

x_{1, 2} = \frac{- 11 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 17}{2 \cdot 2}, x_{2} = \frac{- 11 - 17}{2 \cdot 2}

x = \frac{- 11 + 17}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 11 - 17}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 7

8 x^{2} - 13 x - 6 = 0

x (x + 6) = 216

600 - 200 x + 12 x^{2} = 0

x, x^{2} - 2 x + 184 = 2 x

- x^{2} + 7 x = - 1

What are the solutions to the equation 2x^2+18x=7x+21 ?
The solutions to the equation 2x^2+18x=7x+21 are x= 3/2 ,x=-7
Find the zeros of 2x^2+18x=7x+21
The zeros of 2x^2+18x=7x+21 are x= 3/2 ,x=-7