What are the solutions to the equation -x^2+7x=-1 ?

The solutions to the equation -x^2+7x=-1 are x=-(-7+sqrt(53))/2 ,x=(7+sqrt(53))/2

Find the zeros of -x^2+7x=-1

The zeros of -x^2+7x=-1 are x=-(-7+sqrt(53))/2 ,x=(7+sqrt(53))/2

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- x^{2} + 7 x = - 1

x = - \frac{- 7 + 53}{2}, x = \frac{7 + 53}{2}

Decimal Notation

x = - 0.14005 \dots, x = 7.14005 \dots

Solution steps

- x^{2} + 7 x = - 1

Move

1

to the left side

- x^{2} + 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

7^{2} - 4 (- 1) \cdot 1 = 53

x_{1, 2} = \frac{- 7 \pm 53}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 53}{2 ( - 1 )}, x_{2} = \frac{- 7 - 53}{2 ( - 1 )}

x = \frac{- 7 + 53}{2 ( - 1 )} : - \frac{- 7 + 53}{2}

x = \frac{- 7 - 53}{2 ( - 1 )} : \frac{7 + 53}{2}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 53}{2}, x = \frac{7 + 53}{2}

2 x^{2} - 6 x + 15 = 0

(x - 2)^{2} + x (x + 1) = 24

x, x^{2} + k x + k = x - 2

3 x^{2} + 12 x - 15 = 0

3 y^{2} - 33 y = - 54

What are the solutions to the equation -x^2+7x=-1 ?
The solutions to the equation -x^2+7x=-1 are x=-(-7+sqrt(53))/2 ,x=(7+sqrt(53))/2
Find the zeros of -x^2+7x=-1
The zeros of -x^2+7x=-1 are x=-(-7+sqrt(53))/2 ,x=(7+sqrt(53))/2