What are the solutions to the equation 2y^2-72=0 ?

The solutions to the equation 2y^2-72=0 are y=6,y=-6

Find the zeros of 2y^2-72=0

The zeros of 2y^2-72=0 are y=6,y=-6

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2 y^{2} - 72 = 0

y = 6, y = - 6

Solution steps

2 y^{2} - 72 = 0

Move

72

to the right side

2 y^{2} = 72

Divide both sides by

2

y^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 36, y = - 36

36 = 6

- 36 = - 6

y = 6, y = - 6

2 n^{2} + 4 n - 6 = 0

7 x^{2} - 4 x = - 1

x, 9 x^{2} - 6 x y + y^{2} - 12 x + 4 y + 4 = 0

x, x^{2} ln (y) + e^{y^{2}} = 25 + y

3 x^{2} - 2 x + 6

What are the solutions to the equation 2y^2-72=0 ?
The solutions to the equation 2y^2-72=0 are y=6,y=-6
Find the zeros of 2y^2-72=0
The zeros of 2y^2-72=0 are y=6,y=-6