What are the solutions to the equation solvefor x,x^2+y^2+2x+1=0 ?

The solutions to the equation solvefor x,x^2+y^2+2x+1=0 are x=-1+iy,x=-iy-1

Find the zeros of solvefor x,x^2+y^2+2x+1=0

The zeros of solvefor x,x^2+y^2+2x+1=0 are x=-1+iy,x=-iy-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + y^{2} + 2 x + 1 = 0

x = - 1 + i y, x = - i y - 1

Solution steps

x^{2} + y^{2} + 2 x + 1 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x + y^{2} + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( y ^{2} + 1 )}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot (y^{2} + 1) : 2 i y

x_{1, 2} = \frac{- 2 \pm 2 i y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 i y}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 i y}{2 \cdot 1}

x = \frac{- 2 + 2 i y}{2 \cdot 1} : - 1 + i y

x = \frac{- 2 - 2 i y}{2 \cdot 1} : - i y - 1

The solutions to the quadratic equation are:

x = - 1 + i y, x = - i y - 1

x, 2 x^{2} - 4 x - 1 = 0

\frac{x ^{2} + 10}{2} = 19

x^{2} - 10 x - 4

2 x^{2} + 5 x + 3

x, x^{2} + x y + 2 y^{2} = 18

What are the solutions to the equation solvefor x,x^2+y^2+2x+1=0 ?
The solutions to the equation solvefor x,x^2+y^2+2x+1=0 are x=-1+iy,x=-iy-1
Find the zeros of solvefor x,x^2+y^2+2x+1=0
The zeros of solvefor x,x^2+y^2+2x+1=0 are x=-1+iy,x=-iy-1