What are the solutions to the equation x^2+8x+14=23 ?

The solutions to the equation x^2+8x+14=23 are x=1,x=-9

Find the zeros of x^2+8x+14=23

The zeros of x^2+8x+14=23 are x=1,x=-9

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x^{2} + 8 x + 14 = 23

x = 1, x = - 9

Solution steps

x^{2} + 8 x + 14 = 23

Move

23

to the left side

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

0 = - (x - 5)^{2} + 9

x^{2} - 2 x - 6

x^{2} - 2 x + 4

x^{2} - 3 x = 2 (x + 7)

x (x + 10) = 400

What are the solutions to the equation x^2+8x+14=23 ?
The solutions to the equation x^2+8x+14=23 are x=1,x=-9
Find the zeros of x^2+8x+14=23
The zeros of x^2+8x+14=23 are x=1,x=-9