What are the solutions to the equation 2r^2+60r+400=0 ?

The solutions to the equation 2r^2+60r+400=0 are r=-10,r=-20

Find the zeros of 2r^2+60r+400=0

The zeros of 2r^2+60r+400=0 are r=-10,r=-20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 r^{2} + 60 r + 400 = 0

r = - 10, r = - 20

Solution steps

2 r^{2} + 60 r + 400 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 2 \cdot 400}{2 \cdot 2}

6 0^{2} - 4 \cdot 2 \cdot 400 = 20

r_{1, 2} = \frac{- 60 \pm 20}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 60 + 20}{2 \cdot 2}, r_{2} = \frac{- 60 - 20}{2 \cdot 2}

r = \frac{- 60 + 20}{2 \cdot 2} : - 10

r = \frac{- 60 - 20}{2 \cdot 2} : - 20

The solutions to the quadratic equation are:

r = - 10, r = - 20

10 x^{2} + 48 = 0

a^{2} - 25 = 0

6 t^{2} + 6 t - 12 = 0

x, 3 x^{2} + 6 x - 9 = 0

k^{2} - 6 = 26

What are the solutions to the equation 2r^2+60r+400=0 ?
The solutions to the equation 2r^2+60r+400=0 are r=-10,r=-20
Find the zeros of 2r^2+60r+400=0
The zeros of 2r^2+60r+400=0 are r=-10,r=-20