What are the solutions to the equation 9a^2+3a-24=-4 ?

The solutions to the equation 9a^2+3a-24=-4 are a= 4/3 ,a=-5/3

Find the zeros of 9a^2+3a-24=-4

The zeros of 9a^2+3a-24=-4 are a= 4/3 ,a=-5/3

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9 a^{2} + 3 a - 24 = - 4

a = \frac{4}{3}, a = - \frac{5}{3}

Decimal Notation

a = 1.33333 \dots, a = - 1.66666 \dots

Solution steps

9 a^{2} + 3 a - 24 = - 4

Move

4

to the left side

9 a^{2} + 3 a - 20 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 9 ( - 20 )}{2 \cdot 9}

3^{2} - 4 \cdot 9 (- 20) = 27

a_{1, 2} = \frac{- 3 \pm 27}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- 3 + 27}{2 \cdot 9}, a_{2} = \frac{- 3 - 27}{2 \cdot 9}

a = \frac{- 3 + 27}{2 \cdot 9} : \frac{4}{3}

a = \frac{- 3 - 27}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

a = \frac{4}{3}, a = - \frac{5}{3}

w^{2} = - 99

9 = b^{2}

4 - (5 x + 3)^{2} = 3

6 x^{2} + 5 x - 18 = - 7

w^{2} = - 64

What are the solutions to the equation 9a^2+3a-24=-4 ?
The solutions to the equation 9a^2+3a-24=-4 are a= 4/3 ,a=-5/3
Find the zeros of 9a^2+3a-24=-4
The zeros of 9a^2+3a-24=-4 are a= 4/3 ,a=-5/3