What are the solutions to the equation 4-(5x+3)^2=3 ?

The solutions to the equation 4-(5x+3)^2=3 are x=-2/5 ,x=-4/5

Find the zeros of 4-(5x+3)^2=3

The zeros of 4-(5x+3)^2=3 are x=-2/5 ,x=-4/5

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4 - (5 x + 3)^{2} = 3

x = - \frac{2}{5}, x = - \frac{4}{5}

Decimal Notation

x = - 0.4, x = - 0.8

Solution steps

4 - (5 x + 3)^{2} = 3

Move

4

to the right side

- (5 x + 3)^{2} = - 1

Divide both sides by

- 1

(5 x + 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 3 = 1 : x = - \frac{2}{5}

Solve

5 x + 3 = - 1 : x = - \frac{4}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - \frac{4}{5}

6 x^{2} + 5 x - 18 = - 7

w^{2} = - 64

x^{2} - 10 x + 39 = 0

2 x^{2} + 9 x + 20 = 0

- 4 r^{2} - 4 r - 8 = - 7

What are the solutions to the equation 4-(5x+3)^2=3 ?
The solutions to the equation 4-(5x+3)^2=3 are x=-2/5 ,x=-4/5
Find the zeros of 4-(5x+3)^2=3
The zeros of 4-(5x+3)^2=3 are x=-2/5 ,x=-4/5