What are the solutions to the equation 2x^2+9x+20=0 ?

The solutions to the equation 2x^2+9x+20=0 are x=-9/4+i(sqrt(79))/4 ,x=-9/4-i(sqrt(79))/4

Find the zeros of 2x^2+9x+20=0

The zeros of 2x^2+9x+20=0 are x=-9/4+i(sqrt(79))/4 ,x=-9/4-i(sqrt(79))/4

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2 x^{2} + 9 x + 20 = 0

x = - \frac{9}{4} + i \frac{79}{4}, x = - \frac{9}{4} - i \frac{79}{4}

Solution steps

2 x^{2} + 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

Simplify

9^{2} - 4 \cdot 2 \cdot 20 : 79 i

x_{1, 2} = \frac{- 9 \pm 79 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 79 i}{2 \cdot 2}, x_{2} = \frac{- 9 - 79 i}{2 \cdot 2}

x = \frac{- 9 + 79 i}{2 \cdot 2} : - \frac{9}{4} + i \frac{79}{4}

x = \frac{- 9 - 79 i}{2 \cdot 2} : - \frac{9}{4} - i \frac{79}{4}

The solutions to the quadratic equation are:

x = - \frac{9}{4} + i \frac{79}{4}, x = - \frac{9}{4} - i \frac{79}{4}

- 4 r^{2} - 4 r - 8 = - 7

3 x^{2} - 7 x - 40 = 0

3 x^{2} + x = 10

2 x^{2} + 4 x - 16 = 0

5 x^{2} + 12 x + 2 = 7 x

What are the solutions to the equation 2x^2+9x+20=0 ?
The solutions to the equation 2x^2+9x+20=0 are x=-9/4+i(sqrt(79))/4 ,x=-9/4-i(sqrt(79))/4
Find the zeros of 2x^2+9x+20=0
The zeros of 2x^2+9x+20=0 are x=-9/4+i(sqrt(79))/4 ,x=-9/4-i(sqrt(79))/4