What are the solutions to the equation x^2+10x=3x+44 ?

The solutions to the equation x^2+10x=3x+44 are x=4,x=-11

Find the zeros of x^2+10x=3x+44

The zeros of x^2+10x=3x+44 are x=4,x=-11

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x^{2} + 10 x = 3 x + 44

x = 4, x = - 11

Solution steps

x^{2} + 10 x = 3 x + 44

Move

44

to the left side

x^{2} + 10 x - 44 = 3 x

Move

3 x

to the left side

x^{2} + 7 x - 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 44) = 15

x_{1, 2} = \frac{- 7 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 15}{2 \cdot 1}, x_{2} = \frac{- 7 - 15}{2 \cdot 1}

x = \frac{- 7 + 15}{2 \cdot 1} : 4

x = \frac{- 7 - 15}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 4, x = - 11

0 = x^{2} + 4 x + 1

x + x^{2} - 25 = 15 x + 47

(2 x - 3) (x + 2) = - 3 x

x^{2} - 4 = 23

x^{2} - 80 x + 1200 = 0

What are the solutions to the equation x^2+10x=3x+44 ?
The solutions to the equation x^2+10x=3x+44 are x=4,x=-11
Find the zeros of x^2+10x=3x+44
The zeros of x^2+10x=3x+44 are x=4,x=-11