What are the solutions to the equation z^2-3z=54 ?

The solutions to the equation z^2-3z=54 are z=9,z=-6

Find the zeros of z^2-3z=54

The zeros of z^2-3z=54 are z=9,z=-6

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z^{2} - 3 z = 54

z = 9, z = - 6

Solution steps

z^{2} - 3 z = 54

Move

54

to the left side

z^{2} - 3 z - 54 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 54) = 15

z_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 1}, z_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 1}

z = \frac{- ( - 3 ) + 15}{2 \cdot 1} : 9

z = \frac{- ( - 3 ) - 15}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

z = 9, z = - 6

s^{2} + 10 s + 61

3 x^{2} - 8 x + 4 = 0

3 x^{2} + 7 x = 9

x, x^{2} + y^{2} - 14 x + 2 y + 50 = 0

2 x^{2} + 6 x + 4

What are the solutions to the equation z^2-3z=54 ?
The solutions to the equation z^2-3z=54 are z=9,z=-6
Find the zeros of z^2-3z=54
The zeros of z^2-3z=54 are z=9,z=-6