What are the solutions to the equation (x+3)^2=-22 ?

The solutions to the equation (x+3)^2=-22 are x=sqrt(22)i-3,x=-sqrt(22)i-3

Find the zeros of (x+3)^2=-22

The zeros of (x+3)^2=-22 are x=sqrt(22)i-3,x=-sqrt(22)i-3

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(x + 3)^{2} = - 22

x = 22 i - 3, x = - 22 i - 3

Solution steps

(x + 3)^{2} = - 22

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 22 : x = 22 i - 3

Solve

x + 3 = - - 22 : x = - 22 i - 3

The solutions to the quadratic equation are:

x = 22 i - 3, x = - 22 i - 3

x^{2} - x - 380 = 0

2 x^{2} - 3 x - 1 = 0

0.0057 x^{2} + 0.13 x = 100

124 = x^{2} + 3

2 x^{2} - 5 + 2 = 0

What are the solutions to the equation (x+3)^2=-22 ?
The solutions to the equation (x+3)^2=-22 are x=sqrt(22)i-3,x=-sqrt(22)i-3
Find the zeros of (x+3)^2=-22
The zeros of (x+3)^2=-22 are x=sqrt(22)i-3,x=-sqrt(22)i-3