What are the solutions to the equation 124=x^2+3 ?

The solutions to the equation 124=x^2+3 are x=11,x=-11

Find the zeros of 124=x^2+3

The zeros of 124=x^2+3 are x=11,x=-11

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124 = x^{2} + 3

x = 11, x = - 11

Solution steps

124 = x^{2} + 3

Switch sides

x^{2} + 3 = 124

Move

3

to the right side

x^{2} = 121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 121, x = - 121

121 = 11

- 121 = - 11

x = 11, x = - 11

2 x^{2} - 5 + 2 = 0

x^{2} + 7 x - 98 = 0

x^{2} + 18 x - 4 = 0

a (x + b) - (x + a)^{2} = x^{2}

x^{2} - 16 x = - 55

What are the solutions to the equation 124=x^2+3 ?
The solutions to the equation 124=x^2+3 are x=11,x=-11
Find the zeros of 124=x^2+3
The zeros of 124=x^2+3 are x=11,x=-11