What are the solutions to the equation (b+7)^2=8 ?

The solutions to the equation (b+7)^2=8 are b=2sqrt(2)-7,b=-2sqrt(2)-7

Find the zeros of (b+7)^2=8

The zeros of (b+7)^2=8 are b=2sqrt(2)-7,b=-2sqrt(2)-7

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(b + 7)^{2} = 8

b = 22 - 7, b = - 22 - 7

Decimal Notation

b = - 4.17157 \dots, b = - 9.82842 \dots

Solution steps

(b + 7)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

b + 7 = 8 : b = 22 - 7

Solve

b + 7 = - 8 : b = - 22 - 7

The solutions to the quadratic equation are:

b = 22 - 7, b = - 22 - 7

(1 - x) (1 - x) = 0

x, 4 x^{2} + 4 x y + y^{2} = 21

5 x^{2} - 12 x - 9 = 0

x^{2} + 2 x - 15 = 0

a^{2} - 3 a = 4

What are the solutions to the equation (b+7)^2=8 ?
The solutions to the equation (b+7)^2=8 are b=2sqrt(2)-7,b=-2sqrt(2)-7
Find the zeros of (b+7)^2=8
The zeros of (b+7)^2=8 are b=2sqrt(2)-7,b=-2sqrt(2)-7