What are the solutions to the equation solvefor x,4x^2+4xy+y^2=21 ?

The solutions to the equation solvefor x,4x^2+4xy+y^2=21 are x=(-y+sqrt(21))/2 ,x=-(y+sqrt(21))/2

Find the zeros of solvefor x,4x^2+4xy+y^2=21

The zeros of solvefor x,4x^2+4xy+y^2=21 are x=(-y+sqrt(21))/2 ,x=-(y+sqrt(21))/2

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solve for

x, 4 x^{2} + 4 x y + y^{2} = 21

x = \frac{- y + 21}{2}, x = - \frac{y + 21}{2}

Solution steps

4 x^{2} + 4 x y + y^{2} = 21

Move

21

to the left side

4 x^{2} + 4 x y + y^{2} - 21 = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 4 y x + y^{2} - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 y \pm ( 4 y ) ^{2} - 4 \cdot 4 ( y ^{2} - 21 )}{2 \cdot 4}

(4 y)^{2} - 4 \cdot 4 (y^{2} - 21) = 421

x_{1, 2} = \frac{- 4 y \pm 4 21}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 y + 4 21}{2 \cdot 4}, x_{2} = \frac{- 4 y - 4 21}{2 \cdot 4}

x = \frac{- 4 y + 4 21}{2 \cdot 4} : \frac{- y + 21}{2}

x = \frac{- 4 y - 4 21}{2 \cdot 4} : - \frac{y + 21}{2}

The solutions to the quadratic equation are:

x = \frac{- y + 21}{2}, x = - \frac{y + 21}{2}

5 x^{2} - 12 x - 9 = 0

a^{2} - 3 a = 4

a^{2} - 3 a = 0

6 r^{2} + 9 r + 7 = 0

(x + 188) (x + 380) = 0

What are the solutions to the equation solvefor x,4x^2+4xy+y^2=21 ?
The solutions to the equation solvefor x,4x^2+4xy+y^2=21 are x=(-y+sqrt(21))/2 ,x=-(y+sqrt(21))/2
Find the zeros of solvefor x,4x^2+4xy+y^2=21
The zeros of solvefor x,4x^2+4xy+y^2=21 are x=(-y+sqrt(21))/2 ,x=-(y+sqrt(21))/2