What are the solutions to the equation 2x^2=-x-10 ?

The solutions to the equation 2x^2=-x-10 are x=-1/4+i(sqrt(79))/4 ,x=-1/4-i(sqrt(79))/4

Find the zeros of 2x^2=-x-10

The zeros of 2x^2=-x-10 are x=-1/4+i(sqrt(79))/4 ,x=-1/4-i(sqrt(79))/4

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2 x^{2} = - x - 10

x = - \frac{1}{4} + i \frac{79}{4}, x = - \frac{1}{4} - i \frac{79}{4}

Solution steps

2 x^{2} = - x - 10

Move

10

to the left side

2 x^{2} + 10 = - x

Move

x

to the left side

2 x^{2} + 10 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 10 : 79 i

x_{1, 2} = \frac{- 1 \pm 79 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 79 i}{2 \cdot 2}, x_{2} = \frac{- 1 - 79 i}{2 \cdot 2}

x = \frac{- 1 + 79 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{79}{4}

x = \frac{- 1 - 79 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{79}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{79}{4}, x = - \frac{1}{4} - i \frac{79}{4}

6 x^{2} + 9 = - 55 x

7 = (x - 4)^{2} + 3

3 0^{2} + 1 6^{2} = c^{2}

2 z^{2} - 50 = 100

y^{2} + 6 = 0

What are the solutions to the equation 2x^2=-x-10 ?
The solutions to the equation 2x^2=-x-10 are x=-1/4+i(sqrt(79))/4 ,x=-1/4-i(sqrt(79))/4
Find the zeros of 2x^2=-x-10
The zeros of 2x^2=-x-10 are x=-1/4+i(sqrt(79))/4 ,x=-1/4-i(sqrt(79))/4