What are the solutions to the equation 7=(x-4)^2+3 ?

The solutions to the equation 7=(x-4)^2+3 are x=6,x=2

Find the zeros of 7=(x-4)^2+3

The zeros of 7=(x-4)^2+3 are x=6,x=2

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7 = (x - 4)^{2} + 3

x = 6, x = 2

Solution steps

7 = (x - 4)^{2} + 3

Switch sides

(x - 4)^{2} + 3 = 7

Move

3

to the right side

(x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

3 0^{2} + 1 6^{2} = c^{2}

2 z^{2} - 50 = 100

y^{2} + 6 = 0

7 x^{2} + 4 x = 1

z^{2} = z

What are the solutions to the equation 7=(x-4)^2+3 ?
The solutions to the equation 7=(x-4)^2+3 are x=6,x=2
Find the zeros of 7=(x-4)^2+3
The zeros of 7=(x-4)^2+3 are x=6,x=2