What are the solutions to the equation 7x^2+4x=1 ?

The solutions to the equation 7x^2+4x=1 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7

Find the zeros of 7x^2+4x=1

The zeros of 7x^2+4x=1 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7

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7 x^{2} + 4 x = 1

x = \frac{- 2 + 11}{7}, x = - \frac{2 + 11}{7}

Solution steps

7 x^{2} + 4 x = 1

Move

1

to the left side

7 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

4^{2} - 4 \cdot 7 (- 1) = 211

x_{1, 2} = \frac{- 4 \pm 2 11}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 4 + 2 11}{2 \cdot 7}, x_{2} = \frac{- 4 - 2 11}{2 \cdot 7}

x = \frac{- 4 + 2 11}{2 \cdot 7} : \frac{- 2 + 11}{7}

x = \frac{- 4 - 2 11}{2 \cdot 7} : - \frac{2 + 11}{7}

The solutions to the quadratic equation are:

x = \frac{- 2 + 11}{7}, x = - \frac{2 + 11}{7}

z^{2} = z

x, f = x^{2} + m x + n

(x + 1)^{2} = 49

16 x^{2} - 32 x + 16 = 1

a^{2} + 2 a - 1 = 0

What are the solutions to the equation 7x^2+4x=1 ?
The solutions to the equation 7x^2+4x=1 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7
Find the zeros of 7x^2+4x=1
The zeros of 7x^2+4x=1 are x=(-2+sqrt(11))/7 ,x=-(2+sqrt(11))/7