What are the solutions to the equation a^2+2a-1=0 ?

The solutions to the equation a^2+2a-1=0 are a=-1+sqrt(2),a=-1-sqrt(2)

Find the zeros of a^2+2a-1=0

The zeros of a^2+2a-1=0 are a=-1+sqrt(2),a=-1-sqrt(2)

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a^{2} + 2 a - 1 = 0

a = - 1 + 2, a = - 1 - 2

Decimal Notation

a = 0.41421 \dots, a = - 2.41421 \dots

Solution steps

a^{2} + 2 a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

a_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, a_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

a = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

a = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

a = - 1 + 2, a = - 1 - 2

x^{2} + 2 x - 7 = 17

- 3 a^{2} - 8 a - 5 = 0

x^{2} + 0 x - 4 = 0

n^{2} - 4 n = 11

x^{2} - 7 x - 34 = 0

What are the solutions to the equation a^2+2a-1=0 ?
The solutions to the equation a^2+2a-1=0 are a=-1+sqrt(2),a=-1-sqrt(2)
Find the zeros of a^2+2a-1=0
The zeros of a^2+2a-1=0 are a=-1+sqrt(2),a=-1-sqrt(2)